# Line slope calculator 3x+4y=36

**Straight line given by points A[4; 6] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+9

**Canonical form of the line equation:**3x+4y-36 = 0

**Parametric form of the line equation:**

x = 4t+4

y = -3t+6 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 12

**Y intercept:**y

_{0}= q = 9

**Distance line from the origin:**d

_{0}= 7.2

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[6; 4.5]

**Perpendicular Bisector equation:**4x-3y-10.5 = 0

**Vector OA = (4; 6) ; |OA| = 7.2111**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 35°45'14″ = 0.624 rad**